Your pet hamster sits on a record player whose angular speed is constant. If he moves to a point twice as far from the center, then his linear speed doubles halves remains the same

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meep26wesley

High School

Your pet hamster sits on a record player whose angular speed is constant. If he moves to a point twice as far from the center, then his linear speed

doubles

halves

remains the same

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skyluke89

Verified answer

Answer:
doubles
Explanation:
The relationship between angular speed and linear speed in case of a circular motion is the following:
$v=\omega r$
where
v is the linear speed
$\omega$ is the angular speed
r is the distance from the centre of the circular path
In this proble, the pet hamster moves to a point twice as far from the center; this means that its distance from the centre, r', is doubled:
$r'=2r$
While the angular speed $\omega$ remains the same. Therefore, the new linear speed is
$v'=\omega r' = \omega (2r)=2 \omega r=2v$
So, the correct answer is
the linear speed doubles
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