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Let the original coordinate be at the origin (0, 0)

The coordinates of the point that is 9 units to the left of the y-axis and 6 units above the x-axis is (-9, 6)

If the x-coordinate is 9 units to the left, the resulting x-coordinate will be (x - 9)

Similarly, if the y-axis and 6 units above the x-axis, the resulting coordinate of the y-axis is (y + 6)

Since (x, y) = (0, 0), the required coordinate point will be (0-9, 0+6) = (-9, 6)

Hence the coordinates of the point that is 9 units to the left of the y-axis and 6 units above the x-axis is (-9, 6)

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abidemiokin

Verified answer

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To the left is in the negative direction so-9
above is in the positive direction so+6
point is at (-9,6)