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What is the quotient?

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  • zainebamir540


    Answer:

    Choice B is the answer.

    Step-by-step explanation:

    We have given an expression.

    \frac{2y^{2}-6y-20 }{4y+12} ÷ \frac{y^{2}+5y+6 }{3y^{2}+18y+27 }

    We have to find the quotient of the given expression.

    \frac{2y^{2}-10y+4y-20 }{4(y+3)} ÷ \frac{y^{2}+2y+3y+6 }{3(y^{2}+6y+9) }

    \frac{2y(y-5)+4(y-5)}{4(y+3)} ÷ \frac{y(y+2)+3(y+2)}{3(y^{2}+3y+3y+9) }

    \frac{(2y+4)(y-5)}{4(y+3)} ÷ \frac{(y+2)(y+3)}{3(y+3)(y+3)}

    By changing distribution into multiplication, we have

    \frac{2(y+2)(y-5)}{4(y+3)} × \frac{3(y+3)(y+3)}{(y+2)(y+3)}

    \frac{3(y-5)}{2} which is the answer.