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What is the equation of the line that is parallel to the line y − 1 = 4(x + 3) and passes through the point (4, 32)? y = –x + 33 y = –x + 36 y = 4x − 16 y = 4x + 16
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(Based on todays review)
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jessiccagirtman
Y=4x+16
If the line is parallel to y-1=4(x+3), the slope has to be the same, meaning that the slope has to be 4.
Putting this slope and the point into point slope form, we get the equation:
y-32=4(x-4)
Which can be simplified into slope intercept form:
y-32=4x-16
y=4x-16+32
y=4x+16
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