• 1
  • 38 Views
  • All levels

What is the difference
A
B
C
D

Leave an answer

Our People Answers

0

(Based on todays review)

  • kudzordzifrancis


    Answer:

    D. \frac{x-1}{x^2+3x+2}}

    Step-by-step explanation:

    The given expression is;

    \frac{x}{x^2+3x+2}-\frac{1}{(x+2)(x+1)}

    This is the same as;

    \frac{x}{(x+2)(x+1)}-\frac{1}{(x+2)(x+1)}

    The denominators are the same.

    Subtract the numerators and write one denominator;

    \frac{x-1}{(x+2)(x+1)}}

    Rewrite to get;

    \frac{x-1}{x^2+3x+2}}