Use the cosine double-angle identity cos(2θ) = 1 − 2sin2θ to derive an identity for 2sin2θ

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jdoe0001

Use the cosine double-angle identity cos(2θ) = 1 − 2sin2θ to derive an identity for 2sin2θ

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(Based on todays review)

jdoe0001

Then is just a matter of linear simplification

$\bf cos(2\theta )=1-2sin^2(\theta )\implies 2sin^2(\theta )=1-cos(2\theta )$
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