suppose a parabola has an axis of symmetry at x = -5, a maximum height of 9, and passes through the point (-7,1). write an equation of the parabola in vertex from. Y = -4(x-5)^2+9 Y = -7(x+9)^2 - 5 Y = -0.06(x-5)^2 + 9 Y = -2(x+5)^2 + 9 Help please
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GuessWhosBackBaby
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suppose a parabola has an axis of symmetry at x = -5, a maximum height of 9, and passes through the point (-7,1). write an equation of the parabola in vertex from.
Y = -4(x-5)^2+9
Y = -7(x+9)^2 - 5
Y = -0.06(x-5)^2 + 9
Y = -2(x+5)^2 + 9
Help please...
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rejkjavik
We are given
a parabola has an axis of symmetry at x = -5, a maximum height of 9
so, we get
vertex =(-5,9)
vertex=(h,k)=(-5,9)
so, h=-5 and k=9
we can use vertex form of parabola
we can plug these value
now, it passes through the point (-7,1)
we can use it and then we can solve for a
So, we will get equation of parabola as
..............Answer
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