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imalittlepiglet
High School
If the pressure of a confined gas doubles and its volume decreases by a factor of four, how will its Kelvin temperature change?
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(Based on todays review)
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jamuuj
Answer;
Temperature halves or decreases by a factor of 2
Explanation;
The relationship between pressure, volume, and temperature can be expressed as;
PV/T
and we can compare one state to another by this expression;
P1V1/T1 = P2V2/T2
in this case, we can say P1, V1 and T1 are all equal to 1 and have the pressure doubled, such that P2 = 2 and the volume decreases by a factor of four, so that V = 1/4; then T2 will be equal to;
(1)(1)/1 = (2)(1/4)/T2
1 = 0.5/T2
T2 = 0.5 or 1/2
Temperature will therefore half or decrease by a factor of 2
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