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Given a triangle with b =7, c=3, and A=37°, what is the length of a? Round to the nearest tenth.

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  • frika


    Answer:

    4.9 units

    Step-by-step explanation:

    Use the cosine rule for the triangle ABC:

    a^2=b^2+c^2-2bc\cos\angle A,\\ \\a^2=7^2+3^2-2\cdot 7\cdot 3\cdot \cos37^{\circ},\\ \\a^2\approx 49+9-42\cdot 0.798,\\ \\a^2=58-33.516=24.484,\\ \\a\approx 4.9\ un.