G degrees Celsius how much energy was required to heat the metal please show work

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jangoopkim

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18. A 35.0 G piece of metal wire is heated and the temperature changes from 21°C to 52°C the specific heat of the metal is 0.900 J/G degrees Celsius how much energy was required to heat the metal please show work

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Sarah06109

Answer:
$\boxed {\boxed {\sf 976.5 \ Joules}}$
Explanation:
We are asked to find the heat energy. Since we are given the mass, specific heat, and change in temperature, we should use this formula for heat:
$q=mc\Delta T$
Where m is the mass, c is the specific heat, and ΔT is the change in temperature.
We know this is a 35.0 gram piece of wire, the temperature changes from 21 °C to 52°C and the specific heat is 0.900 J/ g °C.
Therefore,
m= 35.0 g
c= 0.900 J/g °C
ΔT= 52 °C - 21°C= 31°C
Substitute these values into the formula.
$q= (35.0 \ g)(0.900 \ J/g \ \textdegree C)(31 \textdegree C)$
Multiply the first two values. The grams will cancel each other out.
$q=31.5 \ J/ \textdegree C (31 \textdegree C)$
Multiply again. This time, the degrees Celsius cancel each other out, so the final units are Joules.
$q=976.5 \ J$
976.5 Joules of energy were required to heat the piece of metal.
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