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pumpkin1625
High School
Find the zeros of the function. State the multiplicity of any multiple zeros.
y = (x-5)(x+2)^2
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GreenEyes71
Hi,
Pretty simple: if a result of a multiplication is equal to 0, then each factor is equal to 0.
y = f(x) = (x -- 5)(x + 2)² = 0, so:
x₁ -- 5 = 0 ⇒ x₁ = 5.
(x + 2)² = 0 ⇒ x₂ = x₃ = --2, for --2 we have state of multiplicity = 2.
Green eyes.
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