Factor completely: 16x4 – 1 A. (4x + 1)(4x – 1) B. (4x2 + 1)(4x2 – 1) C. (2x + 1)3(2x – 1) D. (4x2 + 1)(2x + 1)(2x – 1). Created by punkrocker4744. middle-school-us - mathematics-us

Remember a^2-b^2=(a-b)(a+b) 16=4^2 x^4=(x^2)^2 so 16x^4-1=(4x^2)^2-(1)^2=(4x^2-1)(4x^2+1) and the 4x^2-1 can be further factored (2x)^2-(1)^2=(2x-1)(2x+1) factoref rom is (4x^2+1)(2x+1)(2x-1) D is answer

Factor completely: 16x4 – 1 A. (4x + 1)(4x – 1) B. (4x2 + 1)(4x2 – 1) C. (2x + 1)3(2x – 1) D. (4x2 + 1)(2x + 1)(2x

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Factor completely: 16x4 – 1 A. (4x + 1)(4x – 1) B. (4x2 + 1)(4x2 – 1) C. (2x + 1)3(2x – 1) D. (4x2 + 1)(2x + 1)(2x – 1)

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Remember a^2-b^2=(a-b)(a+b) 16=4^2 x^4=(x^2)^2 so 16x^4-1=(4x^2)^2-(1)^2=(4x^2-1)(4x^2+1) and the 4x^2-1 can be further factored (2x)^2-(1)^2=(2x-1)(2x+1) factoref rom is (4x^2+1)(2x+1)(2x-1) D is answer
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