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Construct a Rational Function that has a vertical asymptote at X = 6, and a removable
discontinuity at x = -2. Write your function, and explain in detail how you determined your answer.
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(Based on todays review)
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ChickenChild13
Answer:
(x+2)/(x-6)(x+2)
Step-by-step explanation:
We know that vertical asymptotes are found in the denominator, so we can start with 1/(x-6)
x-6 will equal zero at 6, so that is where the VA will be.
For the removable discontinuity (hole), it needs to cancel out in the numerator and denominator. (x+2)/(x-6)(x+2)
when x equals -2, there is an undefined y value.
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