C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion please show work. Created by jangoopkim. chemistry-us

Answer:Explanation:Hello there!In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:Thus, given the values of the enthalpies of formation on the attached file, we obtain:Best regards!

C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion please show work

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C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion please show work

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Answer:
$\Delta H_{comb}=2043.85kJ/mol$
Explanation:
Hello there!
In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:
$\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}$
Thus, given the values of the enthalpies of formation on the attached file, we obtain: $-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol$
Best regards!
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