BEST ANSWER

maybeemmamay

Answer:

Two imaginary solutions

Step-by-step explanation:

What you do is you have to put them into two separate things like this:(x+__)(x+__). When I did this nothing worked so it is two imaginary solutions.

wegnerkolmp2741o

Answer:

2 imaginary solutions

Step-by-step explanation:

3x^2 +6x+4 = 0

We can us the discriminant to determine the roots

b^2 -4ac  where a=3  b=6 and c=4

6^2 -4*3*4

36 - 48

-12

If b^2-4ac>0  then we have 2 real roots

If b^2 -4ac = 0 we have 1 real root

If b^2 -4ac <0  we have 2 complex roots

Since it is less than 0, we have 2 complex roots