PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER. Created by payshencec21. mathematics-us

Answer:one real solutionStep-by-step explanation:We can use the discriminant to find the types of solutionsb^2 -4ac where ax^2 +bx+c=0Since x^2 -8x+16 =0we know a=1 b=-8 and c=16(-8)^2 - 4(1)(16)64 -64 = 0If the discriminant > 0 we have two real solutionsIf the discriminant = 0 we have 1 real solutionsIf the discriminant < 0 we have two complex solutionsSince it equals zero, we have one real solution

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PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

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wegnerkolmp2741o

Answer:
one real solution
Step-by-step explanation:
We can use the discriminant to find the types of solutions
b^2 -4ac where ax^2 +bx+c=0
Since
x^2 -8x+16 =0
we know a=1 b=-8 and c=16
(-8)^2 - 4(1)(16)
64 -64 = 0
If the discriminant > 0 we have two real solutions
If the discriminant = 0 we have 1 real solutions
If the discriminant < 0 we have two complex solutions
Since it equals zero, we have one real solution
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S1NGH

Answer:
One real solution because the answer is $(x-4)^{2}$
Step-by-step explanation:
$x^{2} -8x+16=\\(x-4)(x-4)$
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