50POINTS! What is the escape velocity for lunar module? Lunar module mass 15,200 kg radius of moon 1.74x106m, mass of moon 7.34x1022kg

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meep26wesley

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50POINTS! What is the escape velocity for lunar module? Lunar module mass 15,200 kg radius of moon 1.74x106m, mass of moon 7.34x1022kg

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skyluke89

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Answer:
2.73 km/s
Explanation:
The escape velocity of an object in the gravitational field of the moon is (on the surface of the planet)
$v=\sqrt{\frac{2GM}{r}}$
where
$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant
$M=7.34\cdot 10^{22} kg$ is the mass of the Moon
$r=1.74\cdot 10^6 m$ is the radius of the Moon
As we can see, the escape velocity does not depend on the mass of the lunar module.
Substituting the numbers into the formula, we find
$v=\sqrt{\frac{2(6.67\cdot 10^{-11})(7.34\cdot 10^{22}kg)}{(1.74\cdot 10^6 m)}}=2732 m/s=2.73 km/s$
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keystoneschools

Answer:
2.73 km/s
Explanation:
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