1-sin theta

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Q6: Which is the graph of the polar equation r=1/1-sin theta.

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  • kudzordzifrancis


    Answer:

    The correct answer is C.

    Step-by-step explanation:

    The given equation is;

    r=\frac{1}{1-\sin(\theta)}

    This implies that;

    r(1-\sin(\theta)=1

    r-r\sin(\theta)=1

    Let us write in Cartesian coordinates by substituting;

    r=\sqrt{x^2+y^2} ,y=r\sin(\theta)

    \sqrt{x^2+y^2}-y=1

    \sqrt{x^2+y^2}=y+1

    Square both sides;

    (\sqrt{x^2+y^2})^2=(y+1)^2

    This implies that;

    x^2+y^2=y^2+2y+1

    x^2=2y+1

    y=\frac{1}{2}x^2-\frac{1}{2}

    This is an equation of a parabola that opens upwards with a  y-intercept of -\frac{1}{2}.

    The correct choice is C